AlaskaLinuxUser's Scratchpad

Commit thy works unto the LORD, and thy thoughts shall be established. - Proverbs 16:3

Overclocked the Verizon Galaxy S5

Actually, I'm not the first one to do this. It's been done dozens of times before, and quite frankly, to higher levels. So, why do I make my own kernel overclocked? Well, I do think there is one difference in my kernel overclocking than the others. I don't increase the voltage while adding faster processing power.

Typically, in my kernels I try to focus on battery over performance. However, I like getting the most bang for the buck, too. So, in my kernel, I increased the frequency by 3%, but did not increase the voltage any. This allows the maximum benefit for the same amount of voltage, which equals an increase in performance, without an extra drain on the battery.

Okay, at least not a noticeable drain on the battery. Ohms law is still true, so the Resistance will drop slightly as the frequency went up, because of slightly higher heat, microscopically decreasing the resistance and changing the formula. However, when you increase the voltage, the Power formula changes dramatically.

For example, some fictitious numbers for conceptualization:

Power = Current x Voltage Let's say, (P) 12 = (I) 2 x (E) 6.

If we increase the Voltage, the change is drastic: (P) 14 = (I) 2 x (E) 7.

If we don't increase the voltage, the change is microscopic, only because the change in frequency will ultimately increase the heat (very slightly). In ohm's law, that is I=E/R, so our formula looks like this: Power = Voltage/Resistance x Voltage, or (P) 12 = ([E] 6 / [R] 3) x (E) 6. So if the heat rises microscopically, then the semiconductor resistance lowers microscopically*, then the power will only change microscopically. So, our new fictitious formula looks like this: (P) 12.04 = ([E] 6 / [R] 2.99) x (E) 6.

Either way, you can check out the commit here:

https://github.com/alaskalinuxuser/android_kernel_samsung_klte/commit/dd3e95708f0f4166486fc4341691826ea303d993

Linux - keep it simple.

*Normally, in wire, heat increases cause the resistance to increase. However:

"In a semi-conductor, there is an energy gap between the (filled) valence and the (empty) conduction band. At zero temperature, no charges are in the conduction band and the resistance should be infinite as the system behaves basically like an insulator. If you turn on the temperature, some electrons will start to occupy the conduction band and thus contribute to conduction, lowering the [resistance]."  https://physics.stackexchange.com/users/661/lagerbaer